The ground state energy of hydrogen atom is -13.6 eV. When its electron is in the first excited state, its excitation energy is

Question

The ground state energy of hydrogen atom is -13.6 eV. When its electron is in the first excited state, its excitation energy is (A) 10.2eV (B) 0 (C) 3.4eV (D) 6.8eV

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<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/d93f71854e7e6cf62d6ea7ffac3b13b3-.png" /> 1st excitation energy En2-En1=(-3.4+13.6) =10.2 eV

Q. The ground state energy of hydrogen atom is $- 13.6 e V$ . When its electron is in the first excited state, its excitation energy is

10.2eV

0

3.4eV

6.8eV

1st excitation energy $E_{n 2} - E_{n 1} = (- 3.4 + 13.6)$
$= 10.2 e V$

Q. The ground state energy of hydrogen atom is −13.6eV. When its electron is in the first excited state, its excitation energy is

10.2eV

0

3.4eV

6.8eV

1st excitation energy En2​−En1​=(−3.4+13.6) =10.2eV

Q. The ground state energy of hydrogen atom is $- 13.6 e V$ . When its electron is in the first excited state, its excitation energy is

1st excitation energy $E_{n 2} - E_{n 1} = (- 3.4 + 13.6)$
$= 10.2 e V$