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  4. The ground state energy of hydrogen atom is -13.6 eV. When its electron is in the first excited state, its excitation energy is

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Q. The ground state energy of hydrogen atom is $-13.6 \,eV$. When its electron is in the first excited state, its excitation energy is

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Solution:

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1st excitation energy $E_{n2}-E_{n1}=(-3.4+13.6)$
$=10.2 \,eV$