The ground state energy of hydrogen atom is -13.6 eV. The kinetic energy of the electron in this state is, find the potential energy of electron (in Joule) in the given state.

Question

The ground state energy of hydrogen atom is -13.6 eV. The kinetic energy of the electron in this state is, find the potential energy of electron (in Joule) in the given state. (A) -4.36 × 10-14 J (B) -4.36 × 10-16 J (C) -4.36 × 10-17 J (D) -4.36 × 10-18 J

Tardigrade Admin · Accepted Answer

As, P.E. = -2 K.E. Here, K.E. = 13.6 eV = 2.18 × 10-18 J Hence, P.E. = -2 × 2.18 × 10-18 J = -4.36 × 10-18 J

Q. The ground state energy of hydrogen atom is $- 13.6 e V$ . The kinetic energy of the electron in this state is, find the potential energy of electron (in Joule) in the given state.

$- 4.36 \times 1 0^{- 14} J$

$- 4.36 \times 1 0^{- 16} J$

$- 4.36 \times 1 0^{- 17} J$

$- 4.36 \times 1 0^{- 18} J$

As, $P . E . = - 2 K . E$ .
Here, $K . E . = 13.6 e V = 2.18 \times 1 0^{- 18} J$
Hence, $P . E . = - 2 \times 2.18 \times 1 0^{- 18} J$
$= - 4.36 \times 1 0^{- 18} J$

Q. The ground state energy of hydrogen atom is −13.6eV. The kinetic energy of the electron in this state is, find the potential energy of electron (in Joule) in the given state.

−4.36×10−14J

−4.36×10−16J

−4.36×10−17J

−4.36×10−18J