Question

The ground state energy of hydrogen atom is $-13.6eV$. The energy of second excited state $H{e}^{+}$ ion in $eV$ is :

• A. - 6.04
• B. -27.2
• C. -54.4
• D. -3.4

Answer 1

Answer: (A)

${\left(E\right)}_{n^{th}}={\left(E_{GND}\right)}_H.\frac{Z^2}{n^2}$
$E_{3^{rd}}\left(H{e}^{+}\right)=\left(-13.6eV\right).\frac{2^2}{3^2}=-6.04eV$