1. Tardigrade
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  3. Chemistry
  4. The ground state energy of hydrogen atom is -13.6 eV. The energy of second excited state He+ ion in eV is :

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Q. The ground state energy of hydrogen atom is $-13.6\, eV$. The energy of second excited state $He^+$ ion in $eV$ is :

JEE MainJEE Main 2019Structure of Atom

Solution:

$\left(E\right)_{n^{th}} =\left(E_{GND}\right)_{H} . \frac{Z^{2}}{n^{2}} $
$ E_{3^{rd}} \left(He^{+} \right) =\left(-13.6 eV\right). \frac{2^{2}}{3^{2}} =-6.04\, eV $