The gravitational field in a region is given by vecg = 5N/kg hati + 12 N /kg hatj. The change in the gravitational potential energy of a particle of mass 2 kg when it is taken from the origin to a point (7 m, — 3 m) is :

Question

The gravitational field in a region is given by vecg = 5N/kg hati + 12 N /kg hatj. The change in the gravitational potential energy of a particle of mass 2 kg when it is taken from the origin to a point (7 m, — 3 m) is : (A) 71 J (B) 13√58 j (C) -71 J (D) 1 J

Tardigrade Admin · Accepted Answer

Gravitational field, I = (5 hati+12 hatj) N/kg I = -(dv/dr) v = -[∫ limitsx0 Ix dx+∫ limitsx0 Iy dy] = -[Ix.X+Iy.Y] = -[5 (7-0)+ 12 (-3-0)] = -[35+ (-36)] = 1 J/kg i.e., change in gravitational potential 1 J/kg. Hence change in gravitational potential energy 1 J

Q. The gravitational field in a region is given by $g = 5 N / k g \hat{i} + 12 N / k g \hat{j} .$ The change in the gravitational potential energy of a particle of mass $2 k g$ when it is taken from the origin to a point ( $7 m$ , $—3 m$ ) is :

$71 J$

$1358 j$

$- 71 J$

$1 J$

Q. The gravitational field in a region is given by g​=5N/kgi^+12N/kgj^​. The change in the gravitational potential energy of a particle of mass 2kg when it is taken from the origin to a point (7m, —3m) is :

71J

1358​j

−71J

1J

Gravitational field, I=(5i^+12j^​)N/kg I=−drdv​ v=−[0∫x​Ix​dx+0∫x​Iy​dy] =−[Ix​.X+Iy​.Y] =−[5(7−0)+12(−3−0)] =−[35+(−36)]=1J/kg i.e., change in gravitational potential 1 J/kg. Hence change in gravitational potential energy 1 J

Q. The gravitational field in a region is given by $g = 5 N / k g \hat{i} + 12 N / k g \hat{j} .$ The change in the gravitational potential energy of a particle of mass $2 k g$ when it is taken from the origin to a point ( $7 m$ , $—3 m$ ) is :

$71 J$

$1358 j$

$- 71 J$

$1 J$