Question

The graph of $\log \frac{x}{m}$ vs $\log p$ for an adsorption process is a straight line inclined at an angle of $45^{\circ }$ with intercept equal to $0.6020$. The mass of gas adsorbed per unit mass of adsorbent at the pressure of $0.4atm$ is______ $\times 10^{-1}$ (Nearest integer).
Given: $\log 2=0.3010$

Answer 1

Answer: 16

$\log \frac{x}{m}=\log k+\frac{1}{n}\log P$
$\frac{1}{n}=\tan 45^{\circ }=1$
$\log k=0.6020=\log 4$
$\Rightarrow K=4$
$\therefore \frac{x}{m}=K\cdot P^{1/n}$
$\frac{x}{m}=4(0.4)=1.6$
$\frac{x}{m}=1.6=16\times 10^{-1}$