The graph of kinetic energy of photoelectron versus frequency of the incident radiation is shown for two metals M and N. We may definitely conclude

Question

The graph of kinetic energy of photoelectron versus frequency of the incident radiation is shown for two metals M and N. We may definitely conclude (A) Work function of M > work function of N (B) Work function of M < work function of N (C) Work function of M = work function of N (D) At the threshold frequency of M, the kinetic energy of the photoelectron emitted by M is more than emitted by N

Tardigrade Admin · Accepted Answer

According to Einstein's photoelectric equation, Ek =hv - φ For M, Ek =0, φM = hv1 For N, Ek = 0, φN = hv2 ∴ (φ M/φ N) = (v1/v2) From graph, v1 > v2 ∴ φ M > φ N

Q. The graph of kinetic energy of photoelectron versus frequency of the incident radiation is shown for two metals $M$ and $N$ . We may definitely conclude

Work function of M > work function of N

Work function of M < work function of N

Work function of M = work function of N

At the threshold frequency of M, the kinetic energy of the photoelectron emitted by M is more than emitted by N

According to Einstein's photoelectric equation,
$E_{k} = h_{v} - ϕ$
For $M, E_{k} = 0, ϕ_{M} = h v_{1}$
For $N, E_{k} = 0, ϕ_{N} = h v_{2}$
$∴ \frac{ϕ _{M}}{ϕ _{N}} = \frac{v _{1}}{v _{2}}$
From graph,
$v_{1} > v_{2}$
$∴ ϕ_{M} > ϕ_{N}$

Q. The graph of kinetic energy of photoelectron versus frequency of the incident radiation is shown for two metals M and N. We may definitely conclude