The graph between concentration (X) of the product and time of the reaction A arrow B is of the type I. Hence, graph between -(d[ A ]/d t) and time will be the type:

Question

The graph between concentration (X) of the product and time of the reaction A arrow B is of the type I. Hence, graph between -(d[ A ]/d t) and time will be the type: (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Since [ X ] with time is increasing uniformly so change in concentration of A or B, i.e., (-d[ A ]/d t) or (d[ B ]/d t) is constant

Q. The graph between concentration $(X)$ of the product and time of the reaction $A \to B$ is of the type I. Hence, graph between $- \frac{d [ A ]}{d t}$ and time will be the type:

Since $[X]$ with time is increasing uniformly so change in concentration of A or B, i.e., $\frac{- d [ A ]}{d t}$ or $\frac{d [ B ]}{d t}$ is constant

Q. The graph between concentration (X) of the product and time of the reaction A→B is of the type I. Hence, graph between −dtd[A]​ and time will be the type:

Since [X] with time is increasing uniformly so change in concentration of A or B, i.e., dt−d[A]​ or dtd[B]​ is constant

Q. The graph between concentration $(X)$ of the product and time of the reaction $A \to B$ is of the type I. Hence, graph between $- \frac{d [ A ]}{d t}$ and time will be the type:

Since $[X]$ with time is increasing uniformly so change in concentration of A or B, i.e., $\frac{- d [ A ]}{d t}$ or $\frac{d [ B ]}{d t}$ is constant