The given figure shows two equipotential lines in the x y plane for an electric field. Find the ratio of the magnitude of the x-component of electric field Ex to the y-component electric field Ey in the electric space between these equipotential lines.

Question

The given figure shows two equipotential lines in the x y plane for an electric field. Find the ratio of the magnitude of the x-component of electric field Ex to the y-component electric field Ey in the electric space between these equipotential lines. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Ex=-(d V/d x) ⇒ Ex=-((2/2 × 10-2))=-100 N / C Ey=-((-2/1 × 10-2))=200 N / C

Q. The given figure shows two equipotential lines in the $x y$ plane for an electric field. Find the ratio of the magnitude of the $x$ -component of electric field $E_{x}$ to the $y$ -component electric field $E_{y}$ in the electric space between these equipotential lines.

$E_{x} = - \frac{d V}{d x}$
$\Rightarrow E_{x} = - (\frac{2}{2 \times 1 0 ^{- 2}}) = - 100 N / C$
$E_{y} = - (\frac{- 2}{1 \times 1 0 ^{- 2}}) = 200 N / C$

Q. The given figure shows two equipotential lines in the xy plane for an electric field. Find the ratio of the magnitude of the x-component of electric field Ex​ to the y-component electric field Ey​ in the electric space between these equipotential lines.

Ex​=−dxdV​ ⇒Ex​=−(2×10−22​)=−100N/C Ey​=−(1×10−2−2​)=200N/C

Q. The given figure shows two equipotential lines in the $x y$ plane for an electric field. Find the ratio of the magnitude of the $x$ -component of electric field $E_{x}$ to the $y$ -component electric field $E_{y}$ in the electric space between these equipotential lines.

$E_{x} = - \frac{d V}{d x}$
$\Rightarrow E_{x} = - (\frac{2}{2 \times 1 0 ^{- 2}}) = - 100 N / C$
$E_{y} = - (\frac{- 2}{1 \times 1 0 ^{- 2}}) = 200 N / C$