Question

The general solution of the equation $ta{n}^{2}x=1$ is

• A. $n\pi +\frac{\pi }{4}$
• B. $n\pi -\frac{\pi }{4}$
• C. $n\pi \pm \frac{\pi }{4}$
• D. $2n\pi \pm \frac{\pi }{4}$

Answer 1

Answer: (C)

Given, ${\tan }^{2}x=1$
$\Rightarrow {\tan }^{2}x=1^2$
$\Rightarrow {\tan }^{2}x={\tan }^2\frac{\pi }{4}$
$\Rightarrow x=n\pi \pm \frac{\pi }{4}$