The GCD of two numbers, obtained by three steps of division is 2 and the three quotients are 1,2 and 2 respectively. Find the sum of the numbers.

Question

The GCD of two numbers, obtained by three steps of division is 2 and the three quotients are 1,2 and 2 respectively. Find the sum of the numbers. (A) 24 (B) 36 (C) 20 (D) 40

Tardigrade Admin · Accepted Answer

Let the number be a and b Given, HCF =2 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/f3eb18219fa8bb54426f8b1b7f8dc4de-.png" /> a+b=10+14=24

Q. The GCD of two numbers, obtained by three steps of division is 2 and the three quotients are 1,2 and 2 respectively. Find the sum of the numbers.

24

36

20

40

Let the number be $a$ and $b$
Given, $H CF = 2$

$a + b = 10 + 14 = 24$

Q. The GCD of two numbers, obtained by three steps of division is 2 and the three quotients are 1,2 and 2 respectively. Find the sum of the numbers.

24

36

20

40

Let the number be a and b Given, HCF=2 a+b=10+14=24

Let the number be $a$ and $b$
Given, $H CF = 2$

$a + b = 10 + 14 = 24$