The gas liberated by the electrolysis of Dipotassium succinate solution is :

Question

The gas liberated by the electrolysis of Dipotassium succinate solution is : (A) Ethane (B) Ethyne (C) Ethene (D) Propene

Tardigrade Admin · Accepted Answer

During the electrolysis of potassium succinate, the anion produced is succinate anion.
It gives one ethene molecule and

2 C O_{2}

gas.
The reaction is as follows:

(C H_{2} CO O^{-})_{2} \to C H_{2} = C H_{2} + 2 C O_{2} (g) + 2 e^{-}

At cathode, water molecule get reduce to produce

H_{2}

gas as shown below:

2 H_{2} O + 2 e^{-} \to 2 O H^{-} + H_{2} (g)

O H^{-}

generated here further reacts with

K^{+}

ion present near cathode to form

K O H

.

2 K^{+} + 2 O H^{-} \to 2 K O H

So, the electrolysis of potassium succinate produces

C O_{2}

as well as

H_{2}

gas.

Q. The gas liberated by the electrolysis of Dipotassium succinate solution is :