The fusion of chromite ore (FeCr2O4) with Na2CO3 in air gives a yellow solution upon addition of water. Subsequent treatment with H2SO4 produces an orange solution. The yellow and orange colours, respectively, are due to the formation of

Question

The fusion of chromite ore (FeCr2O4) with Na2CO3 in air gives a yellow solution upon addition of water. Subsequent treatment with H2SO4 produces an orange solution. The yellow and orange colours, respectively, are due to the formation of (A) Na2CrO4 and Na2Cr2O7 (B) Cr(OH)3 and Na2Cr2O7 (C) Cr2(CO3)3 and Fe2(SO4)3 (D) Cr(OH)3 and Na2CrO4

Tardigrade Admin · Accepted Answer

The fusion of chromite ore ( FeCr 2 O 4) with Na 2 CO 3 in air to produce Na 2 CrO 4, a yellow coloured solution in aqueous solution. Subsequent treatment of, it with H 2 SO 4 produces Na 2 Cr 2 O 7, which is orange coloured solution. 8 Na 2 CO 3+4 FeCr 2 O 4+7 O 2 longrightarrow underset textYellow colourNa 2 CrO 4+2 Fe 2 O 3+8 O 2 2 Na 2 CrO 4 xrightarrow2 H + underset textOrangeNa 2 Cr 2 O 7+2 Na ++ H 2 O

Q. The fusion of chromite ore $(F e C r_{2} O_{4})$ with $N a_{2} C O_{3}$ in air gives a yellow solution upon addition of water. Subsequent treatment with $H_{2} S O_{4}$ produces an orange solution. The yellow and orange colours, respectively, are due to the formation of

$N a_{2} C r O_{4}$ and $N a_{2} C r_{2} O_{7}$

$C r (O H)_{3}$ and $N a_{2} C r_{2} O_{7}$

$C r_{2} (C O_{3})_{3}$ and $F e_{2} (S O_{4})_{3}$

$C r (O H)_{3}$ and $N a_{2} C r O_{4}$

Q. The fusion of chromite ore (FeCr2​O4​) with Na2​CO3​ in air gives a yellow solution upon addition of water. Subsequent treatment with H2​SO4​ produces an orange solution. The yellow and orange colours, respectively, are due to the formation of

Na2​CrO4​ and Na2​Cr2​O7​

Cr(OH)3​ and Na2​Cr2​O7​

Cr2​(CO3​)3​ and Fe2​(SO4​)3​

Cr(OH)3​ and Na2​CrO4​

Q. The fusion of chromite ore $(F e C r_{2} O_{4})$ with $N a_{2} C O_{3}$ in air gives a yellow solution upon addition of water. Subsequent treatment with $H_{2} S O_{4}$ produces an orange solution. The yellow and orange colours, respectively, are due to the formation of

$N a_{2} C r O_{4}$ and $N a_{2} C r_{2} O_{7}$

$C r (O H)_{3}$ and $N a_{2} C r_{2} O_{7}$

$C r_{2} (C O_{3})_{3}$ and $F e_{2} (S O_{4})_{3}$

$C r (O H)_{3}$ and $N a_{2} C r O_{4}$