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Question
Mathematics
The function f(x) = sec [ log(x+√1+x2)] is
Q. The function
f
(
x
)
=
sec
[
lo
g
(
x
+
1
+
x
2
)
]
is
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A
odd
B
even
C
neither odd nor even
D
constant
Solution:
f
(
x
)
=
sec
(
ln
(
x
+
1
+
x
2
)
)
=
sec
x
(odd function)
=
even function
∵
sec
x
is an even function.