Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The function f(x)= cot -1 √(x+3) x+ cos -1 √x2+3 x+1 is defined on the set S, where S=
Q. The function
f
(
x
)
=
cot
−
1
(
x
+
3
)
x
+
cos
−
1
x
2
+
3
x
+
1
is defined on the set
S
, where
S
=
1048
127
Inverse Trigonometric Functions
Report Error
A
{
0
,
3
}
15%
B
(
0
,
3
)
27%
C
{
0
,
−
3
}
33%
D
[
−
3
,
0
]
25%
Solution:
x
(
x
+
3
)
≥
0
⇒
x
≥
0
or
x
≤
−
3
and
−
1
≤
x
2
+
3
x
+
1
≤
1
⇒
x
(
x
+
3
)
≤
0
Hence
−
3
≤
x
≤
0
Hence
x
=
0
or
−
3
⇒
x
=
{
0
,
−
3
}