Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The function f(x) = 3x - 5 for x < 3 and - x + 1 for x > 3 and = c for x = 3 and is continuous at x = 3, if c is equal to
Q. The function
f
(
x
)
=
3
x
−
5
for
x
<
3
and
−
x
+
1
for
x
>
3
and =
c
for
x
= 3 and is continuous at
x
= 3, if
c
is equal to
2568
216
Report Error
A
1
B
2
C
3
D
4
Solution:
lim
x
→
3
−
f
(
x
)
=
lim
x
→
3
(
3
x
−
5
)
=
9
−
5
=
4
lim
x
→
3
+
f
(
x
)
=
lim
x
→
3
(
x
+
1
)
=
3
+
1
=
4
∴
lim
x
→
3
f
(
x
)
=
4
=
f
(
3
)
=
c
∴
c
=
4
[
∵
f
is continuous at
x
= 3]