Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The function f(x) = 1 + x( sin x)[ cos x], 0 < x ≤ (π/2) (where [.] is G.I.F.)
Q. The function
f
(
x
)
=
1
+
x
(
sin
x
)
[
cos
x
]
,
0
<
x
≤
2
π
(where [.] is G.I.F.)
1223
188
Application of Derivatives
Report Error
A
is continuous on
(
0
,
2
π
)
55%
B
is strictly increasing in
(
0
,
2
π
)
30%
C
is strictly decreasing in
(
0
,
2
π
)
14%
D
has global maximum value 2
1%
Solution:
For
0
<
x
≤
2
π
;
[
cos
x
]
=
0
Hence,
f
(
x
)
=
1
for all
(
0
,
2
π
]
Trivially
f
(
x
)
is continuous on
(
0
,
2
π
)
This function is neither strictly increasing nor strictly decreasing and its global maximum is 1 .