Q.
The function f:R→R defined by f(x)=[x],∀x∈R , is
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Relations and Functions - Part 2
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Solution:
Let f(x1)=f(x2)⇒[x1]=[x2]⇒x1=x2
[For example, if x1=1.4 and x2=1.5, then [1.4] = [1.5] = 1 ] ∴ f is not one-one .
Also, f is not onto as its range (set of integers) is a proper subset of its co-domain R.