Tardigrade
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Tardigrade
Question
Mathematics
The function f:[-1 / 2,1 / 2] arrow[-π / 2, π / 2] defined by f(x)= sin -1(3 x-4 x3) is
Q. The function
f
:
[
−
1/2
,
1/2
]
→
[
−
π
/2
,
π
/2
]
defined by
f
(
x
)
=
sin
−
1
(
3
x
−
4
x
3
)
is
88
145
Inverse Trigonometric Functions
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A
both one-one and onto
B
neither one-one nor onto
C
onto but not one-one
D
one-one but not onto
Solution:
Since
sin
−
1
(
3
x
−
4
x
3
)
=
3
sin
−
1
x
∈
[
−
π
/2
,
π
/2
]
i.e.,
sin
−
1
x
∈
[
−
π
/6
,
π
/6
]
or
x
∈
[
−
1/2
,
1/2
]
so
f
is onto.
Also
f
′
(
x
)
=
1
−
x
2
3
>
0
for
−
1/2
<
x
<
1/2
.
Therefore,
f
increases on
[
−
1/2
,
1/2
]
and hence
f
is one-one.