The friction of the air causes a vertical retardation equal to 10% of the acceleration due to gravity. Take g = 10m/s2. The maximum height and time to reach the maximum height will be decreased by

Question

The friction of the air causes a vertical retardation equal to 10% of the acceleration due to gravity. Take g = 10m/s2. The maximum height and time to reach the maximum height will be decreased by (A) 9%,9% (B) 11%, 11% (C) 9%,10% (D) 11%,9%

Tardigrade Admin · Accepted Answer

H = (u2/2g) ; H' = (u2/2(g+a)) ta = (u/g) ; t1a = (u/(g + a))

Q. The friction of the air causes a vertical retardation equal to 10% of the acceleration due to gravity. Take $g = 10 m / s^{2}$ . The maximum height and time to reach the maximum height will be decreased by

9%,9%

11%, 11%

9%,10%

11%,9%

$H = \frac{u ^{2}}{2 g}; H^{'} = \frac{u ^{2}}{2 ( g + a )}$
$t_{a} = \frac{u}{g}; t_{a}^{1} = \frac{u}{( g + a )}$

Q. The friction of the air causes a vertical retardation equal to 10% of the acceleration due to gravity. Take g=10m/s2. The maximum height and time to reach the maximum height will be decreased by