Q.
The frequency of whistle of an engine appears to be (4/5)th of initial frequency when it crosses a stationary observer. If the velocity of sound is 330m/s, then the speed of engine will be
n′=v−vsnv………(1) n′′=v+vsnv……..(2)
From (1) and (2), n′′n′=v−vsv+vs .... (3)
According to question, n′n′=45 vs=?v=330m/s ... (4)
From eq. (3) and (4) 45=[330−vs330+vs] ⇒9vs=330 ∴vs=36.6m/s