The frequency of radiation absorbed or emitted when transition occurs between two stationary states with energies E1 (lower) and E2 (higher) is given by

Question

The frequency of radiation absorbed or emitted when transition occurs between two stationary states with energies E1 (lower) and E2 (higher) is given by (A)  upsilon=(E1+E2/h) (B)  upsilon=(E1-E2/h) (C)  upsilon=(E1 × E2/h) (D)  upsilon=(E2 - E1/h)

Tardigrade Admin · Accepted Answer

According to Bohr's postulates:
The frequency of radiation absorbed or emitted when transition occurs between two stationary states that differ in energy by

Δ E

, is given by:

v = \frac{Δ E}{h} = \frac{E _{2} - E _{1}}{h}

Where

E_{1}

and

E_{2}

are the energies of the lower and higher allowed energy states, respectively.
This expression is commonly known as Bohr's frequency rule.

Q. The frequency of radiation absorbed or emitted when transition occurs between two stationary states with energies $E_{1}$ (lower) and $E_{2}$ (higher) is given by

$υ = \frac{E _{1} + E _{2}}{h}$

$υ = \frac{E _{1} - E _{2}}{h}$

$υ = \frac{E _{1} \times E _{2}}{h}$

$υ = \frac{E _{2} - E _{1}}{h}$

Q. The frequency of radiation absorbed or emitted when transition occurs between two stationary states with energies E1​ (lower) and E2​ (higher) is given by

υ=hE1​+E2​​

υ=hE1​−E2​​

υ=hE1​×E2​​

υ=hE2​−E1​​

Q. The frequency of radiation absorbed or emitted when transition occurs between two stationary states with energies $E_{1}$ (lower) and $E_{2}$ (higher) is given by

$υ = \frac{E _{1} + E _{2}}{h}$

$υ = \frac{E _{1} - E _{2}}{h}$

$υ = \frac{E _{1} \times E _{2}}{h}$

$υ = \frac{E _{2} - E _{1}}{h}$