The frequency of oscillation of the springs shown in the figure will be

Question

The frequency of oscillation of the springs shown in the figure will be <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-8y9v7wid18ciuw40.jpg" /> (A) (1/2 π )√(K/m) (B) (1/2 π )√((K1 + K2) m/K1 K2) (C) 2π √(K/m) (D) (1/2 π )√(K1 K2/m (K1 + K2))

Tardigrade Admin · Accepted Answer

n=(1/2 π )√(keq/m)=(1/2 π )√(k1 k2/(k1 + k2) m)

Q. The frequency of oscillation of the springs shown in the figure will be

$\frac{1}{2 π} \frac{K}{m}$

$\frac{1}{2 π} \frac{( K _{1} + K _{2} ) m}{K _{1} K _{2}}$

$2 π \frac{K}{m}$

$\frac{1}{2 π} \frac{K _{1} K _{2}}{m ( K _{1} + K _{2} )}$

$n = \frac{1}{2 π} \frac{k _{e q}}{m} = \frac{1}{2 π} \frac{k _{1} k _{2}}{( k _{1} + k _{2} ) m}$

Q. The frequency of oscillation of the springs shown in the figure will be

2π1​mK​​

2π1​K1​K2​(K1​+K2​)m​​

2πmK​​

2π1​m(K1​+K2​)K1​K2​​​

n=2π1​mkeq​​​=2π1​(k1​+k2​)mk1​k2​​​

$\frac{1}{2 π} \frac{K}{m}$

$\frac{1}{2 π} \frac{( K _{1} + K _{2} ) m}{K _{1} K _{2}}$

$2 π \frac{K}{m}$

$\frac{1}{2 π} \frac{K _{1} K _{2}}{m ( K _{1} + K _{2} )}$

$n = \frac{1}{2 π} \frac{k _{e q}}{m} = \frac{1}{2 π} \frac{k _{1} k _{2}}{( k _{1} + k _{2} ) m}$