Q.
The frequencies of two tuning forks A and B are respectively 1.5% more and 2.5% less than that of the tuning fork C. When A and B are sounded together, 12 beats are produced in 1sec. The frequency of the tuning fork C is
Let the frequency of tuning fork C is xHz.
The frequency of tuning fork A is x+1001.5x=1.015x
The frequency of tuning fork B is x−1002.5x =0.975x
Beat frequency of tuning fork A and B is 1.015x−0.975x=0.04x
Thus, 0.04x=12 ⇒x=0.0412=300Hz