The freezing point of the solution M is

Question

The freezing point of the solution M is (A) 268.7 K (B) 268.5 K (C) 234.2 K (D) 150.9 K

Tardigrade Admin · Accepted Answer

In the given solution ' M ', H 2 O is solute. Therefore, molality of H 2 O =(0.1/0.9 × 46) × 1000=2.4 ⇒ -Δ Tf=Kf text ethanol × 2.4 =2 × 2.4=4.8 ⇒ Tf=155.7-4.8 =150.9 K

Q. The freezing point of the solution $M$ is

268.7 K

268.5 K

234.2 K

150.9 K

In the given solution ' $M$ ', $H_{2} O$ is solute.
Therefore, molality of $H_{2} O = \frac{0.1}{0.9 \times 46} \times 1000 = 2.4$
$\Rightarrow - Δ T_{f} = K_{f}^{ethanol} \times 2.4$
$= 2 \times 2.4 = 4.8$
$\Rightarrow T_{f} = 155.7 - 4.8$
$= 150.9 K$

Q. The freezing point of the solution M is