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  4. The freezing point of the solution M is

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Q. The freezing point of the solution $M$ is

IIT JEEIIT JEE 2008Solutions

Solution:

In the given solution ' $M$ ', $H _{2} O$ is solute.
Therefore, molality of $H _{2} O =\frac{0.1}{0.9 \times 46} \times 1000=2.4$
$\Rightarrow -\Delta T_{f}=K_{f}^{\text {ethanol }} \times 2.4$
$=2 \times 2.4=4.8$
$\Rightarrow T_{f}=155.7-4.8$
$=150.9\, K$