Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The fourth, seventh and tenth terms of a G.P. are p, q, r respectively, then:
Q. The fourth, seventh and tenth terms of a G.P. are
p
,
q
,
r
respectively, then:
1530
197
Sequences and Series
Report Error
A
p
2
=
q
2
+
r
2
11%
B
q
2
=
p
r
71%
C
p
2
=
q
r
13%
D
pq
r
+
pq
+
1
=
0
5%
Solution:
Let
a
be the first term and
r
be common ratio.
Fourth term of G.P.
:
p
=
T
4
=
a
r
3
…
(
i
)
Seventh term of GP. :
q
=
T
7
4
=
a
r
6
....
(
ii
)
Tenth term of G.P. :
r
=
T
10
=
a
r
9
…
(
iii
)
Equ. (i)
×
Equ. (iii):
p
r
=
a
r
3
×
a
r
g
⇒
p
r
=
a
2
r
12
⇒
p
r
=
(
a
r
6
)
2
⇒
p
r
=
q
2