The formula of wavelength of spectral lines for hydrogen atom is

Question

The formula of wavelength of spectral lines for hydrogen atom is (A)  (1/λ )=R( (1/n12)-(1/n22) )  (B)  (1/λ )=R( (1/n22)-(1/n12) )  (C)  (1/λ )=R( (1/n1)-(1/n2) )2  (D)  (1/λ )=R( (1/n2)-(1/n1) )2

Tardigrade Admin · Accepted Answer

Wavelength of spectral lines for hydrogen atom is (1/λ )= overlinev=R( (1/n12)-(1/n22) ) where R is Rydberg constant.

Q. The formula of wavelength of spectral lines for hydrogen atom is

$\frac{1}{λ} = R (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$

$\frac{1}{λ} = R (\frac{1}{n _{2}^{2}} - \frac{1}{n _{1}^{2}})$

$\frac{1}{λ} = R (\frac{1}{n _{1}} - \frac{1}{n _{2}})^{2}$

$\frac{1}{λ} = R (\frac{1}{n _{2}} - \frac{1}{n _{1}})^{2}$

Wavelength of spectral lines for hydrogen atom is $\frac{1}{λ} = \overline{v} = R (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$ where R is Rydberg constant.

Q. The formula of wavelength of spectral lines for hydrogen atom is

λ1​=R(n12​1​−n22​1​)

λ1​=R(n22​1​−n12​1​)

λ1​=R(n1​1​−n2​1​)2

λ1​=R(n2​1​−n1​1​)2

Wavelength of spectral lines for hydrogen atom is λ1​=v=R(n12​1​−n22​1​) where R is Rydberg constant.

$\frac{1}{λ} = R (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$

$\frac{1}{λ} = R (\frac{1}{n _{2}^{2}} - \frac{1}{n _{1}^{2}})$

$\frac{1}{λ} = R (\frac{1}{n _{1}} - \frac{1}{n _{2}})^{2}$

$\frac{1}{λ} = R (\frac{1}{n _{2}} - \frac{1}{n _{1}})^{2}$

Wavelength of spectral lines for hydrogen atom is $\frac{1}{λ} = \overline{v} = R (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$ where R is Rydberg constant.