Question

The formula of wavelength of spectral lines for hydrogen atom is

• A. $ \frac{1}{\lambda }=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right) $
• B. $ \frac{1}{\lambda }=R\left( \frac{1}{n_{2}^{2}}-\frac{1}{n_{1}^{2}} \right) $
• C. $ \frac{1}{\lambda }=R{{\left( \frac{1}{{{n}_{1}}}-\frac{1}{{{n}_{2}}} \right)}^{2}} $
• D. $ \frac{1}{\lambda }=R{{\left( \frac{1}{{{n}_{2}}}-\frac{1}{{{n}_{1}}} \right)}^{2}} $

Answer 1

Answer: (A)

Wavelength of spectral lines for hydrogen atom is $ \frac{1}{\lambda }=\overline{v}=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right) $ where R is Rydberg constant.