The formula of wavelength of spectral lines for hydrogen atom is

Question

The formula of wavelength of spectral lines for hydrogen atom is (A)  (1/λ )=R( (1/n12)-(1/n22) )  (B)  (1/λ )=R( (1/n22)-(1/n12) )  (C)  (1/λ )=R( (1/n1)-(1/n2) )2  (D)  (1/λ )=R( (1/n2)-(1/n1) )2

Tardigrade Admin · Accepted Answer

Formula of spectral lines wavelength for hydrogen atom is as (1/λ )=R( (1/n12)-(1/n22) ) where, R = Rydberg's constant

Q. The formula of wavelength of spectral lines for hydrogen atom is

$\frac{1}{λ} = R (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$

$\frac{1}{λ} = R (\frac{1}{n _{2}^{2}} - \frac{1}{n _{1}^{2}})$

$\frac{1}{λ} = R (\frac{1}{n _{1}} - \frac{1}{n _{2}})^{2}$

$\frac{1}{λ} = R (\frac{1}{n _{2}} - \frac{1}{n _{1}})^{2}$

Formula of spectral lines wavelength for hydrogen atom is as $\frac{1}{λ} = R (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$ where, R = Rydberg's constant

Q. The formula of wavelength of spectral lines for hydrogen atom is

λ1​=R(n12​1​−n22​1​)

λ1​=R(n22​1​−n12​1​)

λ1​=R(n1​1​−n2​1​)2

λ1​=R(n2​1​−n1​1​)2

Formula of spectral lines wavelength for hydrogen atom is as λ1​=R(n12​1​−n22​1​) where, R = Rydberg's constant

$\frac{1}{λ} = R (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$

$\frac{1}{λ} = R (\frac{1}{n _{2}^{2}} - \frac{1}{n _{1}^{2}})$

$\frac{1}{λ} = R (\frac{1}{n _{1}} - \frac{1}{n _{2}})^{2}$

$\frac{1}{λ} = R (\frac{1}{n _{2}} - \frac{1}{n _{1}})^{2}$

Formula of spectral lines wavelength for hydrogen atom is as $\frac{1}{λ} = R (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$ where, R = Rydberg's constant