Question

The formula of brown ring complex compound in $[Fe(H_{2}O{)}_{5}N{O}^{+}]S{O}_4,$ What is the oxidation number of $Fe$ ?

• A. +1
• B. +3
• C. +2
• D. -1

Answer 1

Answer: (A)

$[Fe(H_{2}O{)}_{5}N{O}^{+}]S{O}_4$
$x+0+1-2=0$
$x=+1$