The formula of alum is

Question

The formula of alum is (A) K2SO4 Al2(SO4)3 ⋅ 24H2O (B) K4[Fe(CN)6] (C) K2SO4 Al2(SO4)3⋅ 6H2O (D) Na2CO3 ⋅ 10H2O

Tardigrade Admin · Accepted Answer

General formula for alum is M2SO4.R2(SO4)3.24H2O M= monovalent cation (K+, Na+...) R = Trivalent cation (Al+3, Fe+3) Hence, K2 SO4 Al2 (SO4)3 . 24H2O represent an alum.

Q. The formula of alum is

$K_{2} S O_{4} A l_{2} (S O_{4})_{3} \cdot 24 H_{2} O$

$K_{4} [F e (CN)_{6}]$

$K_{2} S O_{4} A l_{2} (S O_{4})_{3} \cdot 6 H_{2} O$

$N a_{2} C O_{3} \cdot 10 H_{2} O$

General formula for alum is
$M_{2} S O_{4} . R_{2} (S O_{4})_{3} .24 H_{2} O$
$M =$ monovalent cation $(K^{+}, N a^{+} ...)$
$R =$ Trivalent cation $(A l^{+ 3}, F e^{+ 3})$
Hence, $K_{2} S O_{4} A l_{2} (S O_{4})_{3} .24 H_{2} O$ represent an alum.

Q. The formula of alum is

K2​SO4​Al2​(SO4​)3​⋅24H2​O

K4​[Fe(CN)6​]

K2​SO4​Al2​(SO4​)3​⋅6H2​O

Na2​CO3​⋅10H2​O

General formula for alum is M2​SO4​.R2​(SO4​)3​.24H2​O M= monovalent cation (K+,Na+...) R= Trivalent cation (Al+3,Fe+3) Hence, K2​SO4​Al2​(SO4​)3​.24H2​O represent an alum.

$K_{2} S O_{4} A l_{2} (S O_{4})_{3} \cdot 24 H_{2} O$

$K_{4} [F e (CN)_{6}]$

$K_{2} S O_{4} A l_{2} (S O_{4})_{3} \cdot 6 H_{2} O$

$N a_{2} C O_{3} \cdot 10 H_{2} O$

General formula for alum is
$M_{2} S O_{4} . R_{2} (S O_{4})_{3} .24 H_{2} O$
$M =$ monovalent cation $(K^{+}, N a^{+} ...)$
$R =$ Trivalent cation $(A l^{+ 3}, F e^{+ 3})$
Hence, $K_{2} S O_{4} A l_{2} (S O_{4})_{3} .24 H_{2} O$ represent an alum.