The formation of the oxide ion O2-(g) requires first an exothermic and then an endothermic step as shown below O(g) + e−O− (g)ΔH° = −142kJmol−1 O− (g) + e-O2− (g)ΔH° = 844kJmol−1

Question

The formation of the oxide ion O2-(g) requires first an exothermic and then an endothermic step as shown below O(g) + e−O− (g)ΔH° = −142kJmol−1 O− (g) + e-O2− (g)ΔH° = 844kJmol−1 (A) Oxygen is more electronegative (B) O- ion has comparatively larger size than oxygen atom (C) O- ion will tend to resist the addition of another electron (D) Oxygen has high electron affinity

Tardigrade Admin · Accepted Answer

O-1(g) + e longrightarrow O-2(g) Due to the electronic repulsion, amount of the energy is needed to add electron

Q. The formation of the oxide ion $O^{2 -} (g)$ requires first an exothermic and then an endothermic step as shown below
$O (g) + e^{-} O^{-} (g) Δ H^{\circ} = - 142 k J m o l^{- 1}$
$O^{-} (g) + e^{-} O^{2 -} (g) Δ H^{\circ} = 844 k J m o l^{- 1}$

Oxygen is more electronegative

$O^{-}$ ion has comparatively larger size than oxygen atom

$O^{-}$ ion will tend to resist the addition of another electron

Oxygen has high electron affinity

$O^{- 1} (g) + e ⟶ O^{- 2} (g)$
Due to the electronic repulsion, amount of the energy is needed to add electron

Q. The formation of the oxide ion O2−(g) requires first an exothermic and then an endothermic step as shown below O(g)+e−O−(g)ΔH∘=−142kJmol−1 O−(g)+e−O2−(g)ΔH∘=844kJmol−1

Oxygen is more electronegative

O− ion has comparatively larger size than oxygen atom

O− ion will tend to resist the addition of another electron

Oxygen has high electron affinity

O−1(g)+e⟶O−2(g) Due to the electronic repulsion, amount of the energy is needed to add electron

Q. The formation of the oxide ion $O^{2 -} (g)$ requires first an exothermic and then an endothermic step as shown below
$O (g) + e^{-} O^{-} (g) Δ H^{\circ} = - 142 k J m o l^{- 1}$
$O^{-} (g) + e^{-} O^{2 -} (g) Δ H^{\circ} = 844 k J m o l^{- 1}$

$O^{-}$ ion has comparatively larger size than oxygen atom

$O^{-}$ ion will tend to resist the addition of another electron

$O^{- 1} (g) + e ⟶ O^{- 2} (g)$
Due to the electronic repulsion, amount of the energy is needed to add electron