The force required to stretch a wire of cross-section 1 cm 2 to double its length will be: (Given Yong's modulus of the wire =2 × 1011 N / m 2 )

Question

The force required to stretch a wire of cross-section 1 cm 2 to double its length will be: (Given Yong's modulus of the wire =2 × 1011 N / m 2 ) (A) 1 × 107 N (B) 1.5 × 107 N (C) 2 × 107 N (D) 2.5 × 107 N

Tardigrade Admin · Accepted Answer

F =&gamma; A (Δ ℓ/ℓ) =2 × 1011 × 10-4((2 ℓ-ℓ/ℓ)) =2 × 107 N

Q. The force required to stretch a wire of cross-section $1 c m^{2}$ to double its length will be:
(Given Yong's modulus of the wire $= 2 \times 1 0^{11} N / m^{2}$ )

$1 \times 1 0^{7} N$

$1.5 \times 1 0^{7} N$

$2 \times 1 0^{7} N$

$2.5 \times 1 0^{7} N$

$F = γ A \frac{Δ ℓ}{ℓ}$
$= 2 \times 1 0^{11} \times 1 0^{- 4} (\frac{2 ℓ - ℓ}{ℓ})$
$= 2 \times 1 0^{7} N$

Q. The force required to stretch a wire of cross-section 1cm2 to double its length will be: (Given Yong's modulus of the wire =2×1011N/m2 )

1×107N

1.5×107N

2×107N

2.5×107N