The force on a conductor of length l placed in a magnetic field of magnitude B and carrying a current i is given by ( θ is the angle, the conductor makes with the direction of B):

Question

The force on a conductor of length l placed in a magnetic field of magnitude B and carrying a current i is given by ( θ is the angle, the conductor makes with the direction of B): (A)  F=i lB sin θ  (B)  F=i2lB2 sin θ  (C)  F=i l B cos θ  (D)  F=(i2l/B) sin θ

Tardigrade Admin · Accepted Answer

The general equation for the force acting on a current carrying conductor placed in a magnetic field [B] is given by The expression can also be obtained from Lorentz force equation.

Q. The force on a conductor of length $l$ placed in a magnetic field of magnitude $B$ and carrying a current $i$ is given by ( $θ$ is the angle, the conductor makes with the direction of $B$ ):

$F = i lB sin θ$

$F = i^{2} l B^{2} sin θ$

$F = i l B cos θ$

$F = \frac{i ^{2} l}{B} sin θ$

The general equation for the force acting on a current carrying conductor placed in a magnetic field $[B]$ is given by
The expression can also be obtained from Lorentz force equation.

Q. The force on a conductor of length l placed in a magnetic field of magnitude B and carrying a current i is given by ( θ is the angle, the conductor makes with the direction of B):

F=ilBsinθ

F=i2lB2sinθ

F=ilBcosθ

F=Bi2l​sinθ