The force constant of a simple pendulum is

Question

The force constant of a simple pendulum is (A) directly proportional to the mass of the bob (B) directly proportional to the length of the pendulum (C) inversely proportional to both mass of the bob and length of the pendulum (D) independent of the mass of the bob as well as length of the pendulum.

Tardigrade Admin · Accepted Answer

For simple pendulum, the restoring force is given by F = Mg sin θ = Mg (x / l). Since F = kx, hence k = (Mg / l) i.e. k propto M

Q. The force constant of a simple pendulum is

directly proportional to the mass of the bob

directly proportional to the length of the pendulum

inversely proportional to both mass of the bob and length of the pendulum

independent of the mass of the bob as well as length of the pendulum.

For simple pendulum, the restoring force is given by F = Mg sin $θ$ = Mg (x / l). Since F = kx, hence k = (Mg / l) i.e. k $\propto$ M

Q. The force constant of a simple pendulum is

directly proportional to the mass of the bob

directly proportional to the length of the pendulum

inversely proportional to both mass of the bob and length of the pendulum

independent of the mass of the bob as well as length of the pendulum.

For simple pendulum, the restoring force is given by F = Mg sin θ = Mg (x / l). Since F = kx, hence k = (Mg / l) i.e. k ∝ M

For simple pendulum, the restoring force is given by F = Mg sin $θ$ = Mg (x / l). Since F = kx, hence k = (Mg / l) i.e. k $\propto$ M