The foci of a hyperbola coincide with the foci of the ellipse (x2/25) + (y2/9) = 1 If the eccentricity of the hyperbola is 2, then the equation of the tangent to this hyperbola passing through the point (4, 6) is :

Question

The foci of a hyperbola coincide with the foci of the ellipse (x2/25) + (y2/9) = 1 If the eccentricity of the hyperbola is 2, then the equation of the tangent to this hyperbola passing through the point (4, 6) is : (A) 3x - 2y = 0 (B) 2x - 3y + 10 = 0 (C) x - 2y + 8 = 0 (D) 2x - y - 2 = 0

Tardigrade Admin · Accepted Answer

Correct answer is (c) x - 2y + 8 = 0

Q. The foci of a hyperbola coincide with the foci of the ellipse 25x2​+9y2​=1 If the eccentricity of the hyperbola is 2, then the equation of the tangent to this hyperbola passing through the point (4, 6) is :

3x - 2y = 0

2x - 3y + 10 = 0

x - 2y + 8 = 0

2x - y - 2 = 0

Correct answer is (c) x - 2y + 8 = 0

Q. The foci of a hyperbola coincide with the foci of the ellipse $\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1$ If the eccentricity of the hyperbola is 2, then the equation of the tangent to this hyperbola passing through the point (4, 6) is :