The five successive ionization enthalpies of an element are 800, 2427, 3658, 25024 and 32824 kJ mol-1 . The number of valence electrons in the element is :

Question

The five successive ionization enthalpies of an element are 800, 2427, 3658, 25024 and 32824 kJ mol-1 . The number of valence electrons in the element is : (A) 2 (B) 3 (C) 4 (D) 5

Tardigrade Admin · Accepted Answer

Let suppose element X ⇒ X(g) xrightarrow[800]IE1 X overset+(g) xrightarrow[2427]IE2X overset+2(g) xrightarrow[3658]IE3 X overset+3(g) xrightarrow[25024]IE4 X overset+4(g) xrightarrow[32824]IE5 X overset+5(g)

Q. The five successive ionization enthalpies of an element are $800, 2427, 3658, 25024$ and $32824 k J m o l^{- 1}$ . The number of valence electrons in the element is :

2

3

4

5

Let suppose element $X \Rightarrow$
$X_{(g)} I E_{1} 800 X (g) + I E_{2} 2427 X (g) + 2 I E_{3} 3658 X (g) + 3 I E_{4} 25024 X (g) + 4 I E_{5} 32824 X (g) + 5$
$X^{+ 3}$ has stable inert gas configuration as there is high jump after $I E_{3}$
So valence electrons are 3

Q. The five successive ionization enthalpies of an element are 800,2427,3658,25024 and 32824kJmol−1 . The number of valence electrons in the element is :

2

3

4

5

Let suppose element X⇒ X(g)​IE1​800​X(g)+​IE2​2427​X(g)+2​IE3​3658​X(g)+3​IE4​25024​X(g)+4​IE5​32824​X(g)+5​X+3 has stable inert gas configuration as there is high jump after IE3​ So valence electrons are 3

Q. The five successive ionization enthalpies of an element are $800, 2427, 3658, 25024$ and $32824 k J m o l^{- 1}$ . The number of valence electrons in the element is :

Let suppose element $X \Rightarrow$
$X_{(g)} I E_{1} 800 X (g) + I E_{2} 2427 X (g) + 2 I E_{3} 3658 X (g) + 3 I E_{4} 25024 X (g) + 4 I E_{5} 32824 X (g) + 5$
$X^{+ 3}$ has stable inert gas configuration as there is high jump after $I E_{3}$
So valence electrons are 3