The first order decomposition of di-tel-butylperoxide (DTBP) to acetone and ethane is given by the equation: C 8 H 18 O 2( g ) longrightarrow 2 CH 3 COCH 3( g )+ C 2 H 6( g ) The half-life of reaction is 80 min. at 147° C. Starting with pure DTBP (pressure =800 torr) in a flask of constant volume, maintained at 147° C, the time (in min) at which the partial pressure of acetone becomes 1400 torr, is:

Question

The first order decomposition of di-tel-butylperoxide (DTBP) to acetone and ethane is given by the equation: C 8 H 18 O 2( g ) longrightarrow 2 CH 3 COCH 3( g )+ C 2 H 6( g ) The half-life of reaction is 80 min. at 147° C. Starting with pure DTBP (pressure =800 torr) in a flask of constant volume, maintained at 147° C, the time (in min) at which the partial pressure of acetone becomes 1400 torr, is: (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/f72f70b72a88c6e4dfa5317ea277c0e3-.png" /> =100 min Given 2 P=1400 P =700 min Time required for pressure of C 8 H 18 O 2 to be 100 min =3 t1 / 2 =3 × 80=240 min

=100min Given 2P=1400 P=700min Time required for pressure of C8​H18​O2​ to be 100min=3t1/2​ =3×80=240min

$= 100 min$
Given $2 P = 1400$
$P = 700 min$
Time required for pressure of $C_{8} H_{18} O_{2}$ to be $100 min = 3 t_{1/2}$
$= 3 \times 80 = 240 min$