Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na +will be
Q. The first ionization potential of
N
a
is
5.1
e
V
. The value of electron gain enthalpy of
N
a
+
will be
163
211
The s-Block Elements
Report Error
A
−
2.55
e
V
B
−
5.1
e
V
C
−
10.2
e
V
D
+
2.55
e
V
Solution:
Correct answer is (b)
−
5.1
e
V