The first excitation potential of hydrogen atom in the ground state is :

Question

The first excitation potential of hydrogen atom in the ground state is : (A) 13.6 V (B) 3.4 V (C) 10.2 V (D) 1.89 V

Tardigrade Admin · Accepted Answer

From Bohrs concept, energy of atom is nth level is E=(Rhc/n2) Energy required to raise an electron from ground state (n=1) to first excited state (n=2) is E=E2-E1 E=-3.4-(13.4) E=-3.4+13.4=10.2 eV

Q. The first excitation potential of hydrogen atom in the ground state is :

13.6 V

3.4 V

10.2 V

1.89 V

From Bohrs concept, energy of atom is nth level is $E = \frac{R h c}{n ^{2}}$
Energy required to raise an electron from ground state $(n = 1)$ to first excited state $(n = 2)$ is
$E = E_{2} - E_{1}$
$E = - 3.4 - (13.4)$
$E = - 3.4 + 13.4 = 10.2 e V$

Q. The first excitation potential of hydrogen atom in the ground state is :

13.6 V

3.4 V

10.2 V

1.89 V

From Bohrs concept, energy of atom is nth level is E=n2Rhc​ Energy required to raise an electron from ground state (n=1) to first excited state (n=2) is E=E2​−E1​ E=−3.4−(13.4) E=−3.4+13.4=10.2eV

From Bohrs concept, energy of atom is nth level is $E = \frac{R h c}{n ^{2}}$
Energy required to raise an electron from ground state $(n = 1)$ to first excited state $(n = 2)$ is
$E = E_{2} - E_{1}$
$E = - 3.4 - (13.4)$
$E = - 3.4 + 13.4 = 10.2 e V$