The figure shows variation of photocurrent with anode potential for a photo-sensitive surface for three different radiations. Let Ia,Ib and Ic be the intensities and va,vb and vc be the frequencies for the curves a,b and c respectively. Then

Question

The figure shows variation of photocurrent with anode potential for a photo-sensitive surface for three different radiations. Let Ia,Ib and Ic be the intensities and va,vb and vc be the frequencies for the curves a,b and c respectively. Then <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-orrnvfbljnhq.png" /> (A) va=vb and Ia≠ Ib (B) va=vc and Ia=Ic (C) va=vb and Ia=Ib (D) vb=vc and Ib=Ic

Tardigrade Admin · Accepted Answer

Saturation current is proportional to intensity while stopping potential increases with increase in frequency. Hence, va=vb while Ia < Ib

Q. The figure shows variation of photocurrent with anode potential for a photo-sensitive surface for three different radiations. Let $I_{a}, I_{b}$ and $I_{c}$ be the intensities and $v_{a}, v_{b}$ and $v_{c}$ be the frequencies for the curves $a, b$ and $c$ respectively. Then

$v_{a} = v_{b} an d I_{a} \neq = I_{b}$

$v_{a} = v_{c} an d I_{a} = I_{c}$

$v_{a} = v_{b} an d I_{a} = I_{b}$

$v_{b} = v_{c} an d I_{b} = I_{c}$

Saturation current is proportional to intensity while stopping potential increases with increase in frequency. Hence,
$v_{a} = v_{b}$ while $I_{a} < I_{b}$

Q. The figure shows variation of photocurrent with anode potential for a photo-sensitive surface for three different radiations. Let Ia​,Ib​ and Ic​ be the intensities and va​,vb​ and vc​ be the frequencies for the curves a,b and c respectively. Then

va​=vb​andIa​=Ib​

va​=vc​andIa​=Ic​

va​=vb​andIa​=Ib​

vb​=vc​andIb​=Ic​