The figure shows standing de Broglie waves due to the revolution of electron in a certain orbit of hydrogen atom. Then the expression for the orbit radius is (all notations have their usual meanings)

Question

The figure shows standing de Broglie waves due to the revolution of electron in a certain orbit of hydrogen atom. Then the expression for the orbit radius is (all notations have their usual meanings) (A) ( h 2 ∈0/π me 2) (B) (4 h2 ϵ0/π m e2) (C) (9 h2 ∈0/π m e2) (D) none

Tardigrade Admin · Accepted Answer

Number of stationary waves is 6 i.e., n =6 r=(n2 ε02 h2/π m e2) =(36 ε02 h2/π m e2)

Q. The figure shows standing de Broglie waves due to the revolution of electron in a certain orbit of hydrogen atom. Then the expression for the orbit radius is (all notations have their usual meanings)

$\frac{h ^{2} \in _{0}}{πm e ^{2}}$

$\frac{4 h ^{2} ϵ _{0}}{πm e ^{2}}$

$\frac{9 h ^{2} \in _{0}}{πm e ^{2}}$

none

Number of stationary waves is $6$ i.e., $n = 6$
$r = \frac{n ^{2} ε _{0}^{2} h ^{2}}{πm e ^{2}}$
$= \frac{36 ε _{0}^{2} h ^{2}}{πm e ^{2}}$

Q. The figure shows standing de Broglie waves due to the revolution of electron in a certain orbit of hydrogen atom. Then the expression for the orbit radius is (all notations have their usual meanings)

πme2h2∈0​​

πme24h2ϵ0​​

πme29h2∈0​​

none

Number of stationary waves is 6 i.e., n=6 r=πme2n2ε02​h2​ =πme236ε02​h2​

$\frac{h ^{2} \in _{0}}{πm e ^{2}}$

$\frac{4 h ^{2} ϵ _{0}}{πm e ^{2}}$

$\frac{9 h ^{2} \in _{0}}{πm e ^{2}}$

Number of stationary waves is $6$ i.e., $n = 6$
$r = \frac{n ^{2} ε _{0}^{2} h ^{2}}{πm e ^{2}}$
$= \frac{36 ε _{0}^{2} h ^{2}}{πm e ^{2}}$