The figure shows some of the electric field lines corresponding to an electric field. The figure suggests

Question

The figure shows some of the electric field lines corresponding to an electric field. The figure suggests <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/8fc4ca1e44e502a571b5cddcaf537794-.png" /> (A) EA> EB> EC (B) EA=EB=EC (C) EA=EC>EB (D) EA> EC> EB

Tardigrade Admin · Accepted Answer

Electric field intensity at a particular point is directly proportional to the number of electric line of forces crossing per unit area.

\Rightarrow E_{A} = E_{C} .. (i)

As, density of electric line of force in region

A

and

C

is more as compared to

B

.
Hence,

E_{A} > E_{A}

From Eqs., (i) and (ii), were get

E_{A} = E_{C} > E_{B}

Q. The figure shows some of the electric field lines corresponding to an electric field. The figure suggests

$E_{A} > E_{B} > E_{C}$

$E_{A} = E_{B} = E_{C}$

$E_{A} = E_{C} > E_{B}$

$E_{A} > E_{C} > E_{B}$

Q. The figure shows some of the electric field lines corresponding to an electric field. The figure suggests

EA​>EB​>EC​

EA​=EB​=EC​

EA​=EC​>EB​

EA​>EC​>EB​

$E_{A} > E_{B} > E_{C}$

$E_{A} = E_{B} = E_{C}$

$E_{A} = E_{C} > E_{B}$

$E_{A} > E_{C} > E_{B}$