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Q.
The figure shows some of the electric field lines corresponding to an electric field. The figure suggests
Electric Charges and Fields
Solution:
Electric field intensity at a particular point is directly proportional to the number of electric line of forces crossing per unit area.
$\Rightarrow E_{A}=E_{C}..(i)$
As, density of electric line of force in region $A$ and $C$ is more as compared to $B$.
Hence, $E_{A} >E_{A}$
From Eqs., (i) and (ii), were get
$E_{A}= E_{C } >E_{B}$
