Question

The figure shows $P-V$ diagram of a thermodynamic cycle. Which corresponding curve is correct?

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

$A\to BV=$ constant
$\because PV=RT$
Compare with $y=mx$
$P-T$ graph is a straight line which must passes from origin
$A\to B$ volume constant, $P$-increasing, $T$-increasing.
$B\to C$ pressure constant, volume - increasing, temperature - increasing
$B\to CP=$ constant, origin $P-T$ graph is a straightline parallel to $v$-axis
$C\to DV=$ constant then
$P=\frac{R}{V}T$
$P-T$ graph is straight line must passes from origin
$D\to AP=$ constant
$P-T$ graph is a straightline parallel to $T$-axis.