The figure shows graphs of pressure versus density for an ideal gas at two temperatures T1 and T2, then

Question

The figure shows graphs of pressure versus density for an ideal gas at two temperatures T1 and T2, then (A) T1 > T2 (B) T1 = T2 (C) T1 < T2 (D) Nothing can be predicted

Tardigrade Admin · Accepted Answer

pV = nRT = (m/M)RT ⇒ (P/m / V) = (RT/M) ⇒ (p/ ho) = (RT/M) ⇒ (p/ ρ) propto T ∴ for a given gas M is constant Temperature is directly proportional to the slope of p - ρ graph. So, T1 > T2 .

Q. The figure shows graphs of pressure versus density for an ideal gas at two temperatures $T_{1}$ and $T_{2}$ , then

$T_{1} > T_{2}$

$T_{1} = T_{2}$

$T_{1} < T_{2}$

Nothing can be predicted

$p V = n RT = \frac{m}{M} RT$
$\Rightarrow \frac{P}{m / V} = \frac{RT}{M} \Rightarrow \frac{p}{h o} = \frac{RT}{M}$
$\Rightarrow \frac{p}{ρ} \propto T$
$∴$ for a given gas M is constant
Temperature is directly proportional to the slope of p - $ρ$ graph. So, $T_{1} > T_{2}$ .

Q. The figure shows graphs of pressure versus density for an ideal gas at two temperatures T1​ and T2​, then

T1​>T2​

T1​=T2​

T1​<T2​