The figure shows elliptical orbit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If t1 is the time for the planet to move from C to D and t2 is the time to move from A to B then :

Question

The figure shows elliptical orbit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If t1 is the time for the planet to move from C to D and t2 is the time to move from A to B then : (A) t 1=4 t 2 (B) t 1=2 t 2 (C) t 1= t 2 (D) t 1> t 2

Tardigrade Admin · Accepted Answer

According to Keplerâs law, the areal velocity of a planet around the sun always remains constant. SCD: A1- t1 (areal velocity constant) SAB: A2 - t2 (A1/t1)=(A2/t2), t1=t2. (A1/A2), (given A1 = 2A2) =t2. (2A2/A2) ∴ t1=2t2

Q. The figure shows elliptical orbit of a planet m about the sun $S$ . The shaded area $SC D$ is twice the shaded area $S A B$ . If $t_{1}$ is the time for the planet to move from $C$ to $D$ and $t_{2}$ is the time to move from $A$ to $B$ then :

$t_{1} = 4 t_{2}$

$t_{1} = 2 t_{2}$

$t_{1} = t_{2}$

$t_{1} > t_{2}$

Q. The figure shows elliptical orbit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If t1​ is the time for the planet to move from C to D and t2​ is the time to move from A to B then :

t1​=4t2​

t1​=2t2​

t1​=t2​

t1​>t2​

According to Kepler’s law, the areal velocity of a planet around the sun always remains constant. SCD : A1​−t1​ (areal velocity constant) SAB : A2​−t2​ t1​A1​​=t2​A2​​, t1​=t2​.A2​A1​​,(given A1​=2A2​) =t2​.A2​2A2​​ ∴t1​=2t2​

Q. The figure shows elliptical orbit of a planet m about the sun $S$ . The shaded area $SC D$ is twice the shaded area $S A B$ . If $t_{1}$ is the time for the planet to move from $C$ to $D$ and $t_{2}$ is the time to move from $A$ to $B$ then :

$t_{1} = 4 t_{2}$

$t_{1} = 2 t_{2}$

$t_{1} = t_{2}$

$t_{1} > t_{2}$