The figure shows an electric line of force which curves along a circular arc. The magnitude of electric field intensity is the same at all points on this curve and is equal to E . If the potential at A is V , then the potential at B is

Question

The figure shows an electric line of force which curves along a circular arc. The magnitude of electric field intensity is the same at all points on this curve and is equal to E . If the potential at A is V , then the potential at B is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-4orc4bfwhvauk3lj.jpg" /> (A) V-ERθ  (B) V-2ERsin (θ /2) (C) V+ERθ  (D) V+2ERsin (θ /2)

Tardigrade Admin · Accepted Answer

VA-VB= Work done by the electric field per unit charge. Work done from A to B=ERθ ∴ VB=VA-ERθ =V-ERθ

Q. The figure shows an electric line of force which curves along a circular arc. The magnitude of electric field intensity is the same at all points on this curve and is equal to $E$ . If the potential at $A$ is $V$ , then the potential at $B$ is

$V - ERθ$

$V - 2 ER s in \frac{θ}{2}$

$V + ERθ$

$V + 2 ER s in \frac{θ}{2}$

$V_{A} - V_{B} =$ Work done by the electric field per unit charge.
Work done from $A$ to $B = ERθ$
$∴ V_{B} = V_{A} - ERθ = V - ERθ$

Q. The figure shows an electric line of force which curves along a circular arc. The magnitude of electric field intensity is the same at all points on this curve and is equal to E . If the potential at A is V , then the potential at B is

V−ERθ

V−2ERsin2θ​

V+ERθ

V+2ERsin2θ​